SOLUTION: There were 36 nickels, dimes and quarters whose value was $6. If there were three times as many quarters as nickels, how many coins of each kind were there?

Question 67296This question is from textbook An Incremental Development
: There were 36 nickels, dimes and quarters whose value was $6. If there were three times as many quarters as nickels, how many coins of each kind were there?
This question is from textbook An Incremental Development

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
N+D+3N=36
5N+10D+25*3N=600
4N+D=36
4N=36-D
N=9-D/4
THUS
5(9-D/4)+10D+25*3(9-D/4)=600
45-5D/4+10D+75(9-D/4)=600
45-5D/4+10D+675-75D/4=600
10D-80D/4=600-45-675
(40D-80D)/4=-120
-40D/4=-120
-40D=-480
D=-480/-40
D=12 NUMBER OF DIMES
N+12=3N=36
4N=36-12
4N=24
N=24/4
N=6 NUMBER OF NICKELS
THUS 3N=18 THE NUMBER OF QUARTERS
PROOF
12*10+6*5+18*25=600
120+30+450=600
600=600
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