SOLUTION: Above, Simone invested $1000 at 8% compounded continuously. In how many years will she have $2000?

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Question 627620: Above, Simone invested $1000 at 8% compounded continuously. In how many years will she have $2000?

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
A = $1000e^(.08*t)
$2000 = $1000e^(.08*t)
2= e^(.08*t)
ln(2) = .08 ln e^t
ln(2)/.08 = t
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