SOLUTION: I need help coming up with an equation and solution to the following problem:
A group of 21 friends each had the same 8 coins. altogether the group had $8.61. if each friend had o
Algebra.Com
Question 608365: I need help coming up with an equation and solution to the following problem:
A group of 21 friends each had the same 8 coins. altogether the group had $8.61. if each friend had onlyquarters, dimes, or pennies, how many pennies did they have altogether?
Thanks,
DR
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
If each of the 21 people had the same set of coins, then they each contributed the same amount of money, namely $8.61 divided by 21, or $0.41. The only way to make 41 cents out of 8 coins consisting of quarters, dimes, and pennies is 1 quarter, 1 dime, and 6 pennies. So, 6 pennies times 21...
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
I need help coming up with a equation and solution to this problem:
More than 20 and... (answered by solver91311)
I am having issues coming up with the algebraic problem for the following:
You and... (answered by ikleyn,josmiceli)
hello, i have a quiz coming up and i need help :) please SHOW work and EXPLAIN how to do... (answered by rfer)
i need help coming up with a real life situation to go with the equation... (answered by ewatrrr)
You invest $7200 in two accounts paying 8% and 10% annual interest. At the end of the... (answered by mananth,jorel1380)
(((The Schwarzschild radius describes the critical valie to which the radius of a massive (answered by LtAurora)
I need help coming up with an equation from the following question: "Jim weighs 40... (answered by Fombitz)
Hello could you please help me solve this equation? 8(3z-5)=34 is the equation and I am... (answered by Alan3354)
