SOLUTION: mr.hart made two investments, one at 4.5% and the other at 3%. the amount invested at 3% exceeded the amount invested at 4.5% by $300. if his total annual income was $84, find the

Algebra.Com
Question 601862: mr.hart made two investments, one at 4.5% and the other at 3%. the amount invested at 3% exceeded the amount invested at 4.5% by $300. if his total annual income was $84, find the amount invested at each rate.
Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
mr.hart made two investments, one at 4.5% and the other at 3%. the amount invested at 3% exceeded the amount invested at 4.5% by $300. if his total annual income was $84, find the amount invested at each rate.
.
Let x = amount ($) invested at 4.5%
then
x+300 = amount ($) invested at 3%
.
.045x + .03(x+300) = 84
.045x + .03x+9 = 84
.075x+9 = 84
.075x = 75
x = $1000 (invested at 4.5%)
.
invested at 3%:
x+300 = 1000+300 = $1300

RELATED QUESTIONS

Natsumi receives $126 per year in simple interest from three investments. Part is... (answered by richwmiller)
mr west invested $7200, part at 4% and the rest at 5%. if the annual incomes from both... (answered by lwsshak3)
Santiago receives ​$309 per year in simple interest from three investments. Part is (answered by stanbon)
Kenneth invested some money at 4% and $7000 less than twice that amount at 9%. If x... (answered by jorel1380)
Mr. Garcia invested $100,000 part at 5% and part at 3%. If the annual income is $4,200,... (answered by macston)
How can $3,960 be invested, part of it at 4% and the remainder at 5%, so that the two... (answered by stanbon)
Roberto invested some money at 2.5% and then invested $3000 more than twice this amount... (answered by stanbon)
Two investments were made totaling $10,500. Part of the $10,500 was invested at 9% and... (answered by partha_ban)
You have two investments. One earns 5%, the other 3%. If you have $10,000 invested and... (answered by ewatrrr)