SOLUTION: Mona invests $300 at 4% yearly interest. How much does she have to invest at 9% so that the total yearly interest from the two investments exceeds $48?

Algebra.Com
Question 591051: Mona invests $300 at 4% yearly interest. How much does she have to invest at 9% so that the total yearly interest from the two investments exceeds $48?


Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Mona invests $300 at 4% yearly interest. How much does she have to invest at 9% so that the total yearly interest from the two investments exceeds $48?
--------
Interest1: 300*0.04 = 12
--
Equation:
0.09x + 12 > 48
0.09x > 36
x > $400
===============
Cheers,
Stan H.

RELATED QUESTIONS

Mona invests $1000 at 8% yearly interest. How much does she have to invest at 9% so that (answered by lwsshak3)
Mona invests $1000 at 7% yearly interest. How much does she have to invest at 6% so that... (answered by addingup)
Suppose that Annette invests $7000 at 7%. How much must she invest at 11% so that the... (answered by mananth)
Marcia has $18000 to invest in two different investments. She invest $10000 at 4% yearly... (answered by josmiceli)
Marcia has $18,000 to invest in two different investment. she invested $10,000 at 4%... (answered by ikleyn)
I have so many problems with word problems and I really don't know how to set up the... (answered by checkley77)
1. George has $700 to invest. Suppose he invests $300 at 6% interest. At what rate must... (answered by VFBundy,MathTherapy)
Melissa is planning to invest a total of $17,000 in two accounts. If she invests $10,000 (answered by josmiceli)
Melinda invested three times as much money at 9% yearly interest as she did at 7%. Her... (answered by stanbon)