SOLUTION: A box of coins containing dimes and nickels totaling $7.35. If there are 12 more dimes than nickels, how many of each type are in the box?

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Question 583089: A box of coins containing dimes and nickels totaling $7.35. If there are 12 more dimes than nickels, how many of each type are in the box?
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
dimes are .10 nickels are .05
.1d%2B.05n=7.35
n%2B12=d
.1%28n%2B12%29%2B.05n=7.35
.1n%2B1.2%2B.05n=7.35
.15n=6.15
n=41
d=53
check
.1d%2B.05n=7.35
.1%2853%29%2B.05%2841%29=7.35
5.3%2B2.05=7.35
7.35=7.35
correct