SOLUTION: Clara earned $360 in simple interest on a 12-month bank certificate of deposit. If the interest rate had been 3% higher, she would have earned the same amount of money by depositin

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Question 57493: Clara earned $360 in simple interest on a 12-month bank certificate of deposit. If the interest rate had been 3% higher, she would have earned the same amount of money by depositing $1,000 less. How much money did Clara deposit, and what was her interest rate?
PLEASE HELP ME:(

Answer by hayek(51) About Me  (Show Source):
You can put this solution on YOUR website!
Simple interest formula is Interest = (Deposit Amt. (P)) * (Interest Rate (i))
(I use P as the Deposit Amount as this is often call the Principal Amount)
The problems tells us Clara earned $360 in interest.
The problem also tells us if the interest were 3% more (i.e. i+0.03), she would have earned the same amount (360) if she deposited 1,000 less (i.e. (P-1000)).
Thus, we have the following two formulas:
360=P%2Ai (Eq. 1)
360=%28P-1000%29%2A%28i%2B.03%29 (Eq. 2)
Solve Eq.1 for P:
P=360%2Fi (Eq. 3)
Plug the Eq.3 result into Eq. 2:
360=%28%28360%2Fi%29-1000%29%2A%28i%2B.03%29
Now, distribute:
360=%28360%2Fi%29%28i%29%2B%28360%2Fi%29%280.03%29-1000i-1000%28.03%29
360=360%2B10.8%2Fi-1000i-30
0=10.8%2Fi-1000i-30
Multiply both sides by i:
0=10.8-1000i%5E2-30i
1000i%5E2%2B30i-10.8=0
Solving using the quadratic formula gives two solutions: i=.09, -.12.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ai%5E2%2Bbi%2Bc=0 (in our case 1000i%5E2%2B30i%2B-10.8+=+0) has the following solutons:

i%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%2830%29%5E2-4%2A1000%2A-10.8=44100.

Discriminant d=44100 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-30%2B-sqrt%28+44100+%29%29%2F2%5Ca.

i%5B1%5D+=+%28-%2830%29%2Bsqrt%28+44100+%29%29%2F2%5C1000+=+0.09
i%5B2%5D+=+%28-%2830%29-sqrt%28+44100+%29%29%2F2%5C1000+=+-0.12

Quadratic expression 1000i%5E2%2B30i%2B-10.8 can be factored:
1000i%5E2%2B30i%2B-10.8+=+1000%28i-0.09%29%2A%28i--0.12%29
Again, the answer is: 0.09, -0.12. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1000%2Ax%5E2%2B30%2Ax%2B-10.8+%29


So, Clara's interest rate (i) was 9%.
Plug that into Eq.1 to get her total deposit: 360=p(.09)
P=$4000