SOLUTION: class 12l of 12%alcahol solutioni mixxed with a 20% alcahol solution to get a 14% solution how many liters of 20% solution are needed
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Question 568025: class 12l of 12%alcahol solutioni mixxed with a 20% alcahol solution to get a 14% solution how many liters of 20% solution are needed
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
class 12L of 12% alcahol solutioni mixxed with a 20% alcahol solution to get a 14% solution how many liters of 20% solution are needed
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alcohol + alcohol = alcohol
0.12*12L + 0.20x = 0.14(121+x)
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Multiply thru by 100
12*12L + 20x = 14*12L + 14x
6x = 2*12L
x = (1/3)(12L)
x = 4 L (amt of 20% solution needed)
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Cheers,
Stan H.
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