SOLUTION: Suppose that Annette invests $7000 at 7%. How much must she invest at 11% so that the total yearly interest from the two investments exceeds $974?
Algebra.Com
Question 563840: Suppose that Annette invests $7000 at 7%. How much must she invest at 11% so that the total yearly interest from the two investments exceeds $974?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let her invest $x @ 11%
7000 @ 7%
Interest =974
0.11x+0.07*7000=974
multiply by 100
11x+49000=974*100
11x= 97400-49000
11x=48400
x=4400 @ 11%
RELATED QUESTIONS
Mona invests $1000 at 7% yearly interest. How much does she have to invest at 6% so that... (answered by addingup)
Mona invests $300 at 4% yearly interest. How much does she have to invest at 9% so that... (answered by stanbon)
Mona invests $1000 at 8% yearly interest. How much
does she have to invest at 9% so that (answered by lwsshak3)
Sally has $70,000 to invest. She invests some money at 7% interest and the rest at 11%.... (answered by reviewermath)
A woman invests $8000
-Part of it at 11% and the remainder at 12%
-Her yearly total... (answered by DrBeeee)
willie cabaysa invests $10200 at 8 1/2%. how much money must he invest at 7% so that his... (answered by gksetu,richwmiller)
Marcia has $18000 to invest in two different investments. She invest $10000 at 4% yearly... (answered by josmiceli)
If Fran invests $8200 at 6% per year, how much additional money must she invest at 8% to... (answered by plydry28)
If Fran invests $8200 at 6% per year, how much additional money must she invest at 8% to... (answered by checkley77)