SOLUTION: Warren has 40 coins (all nickels, dimes, and quarters) worth $4.05. He has 7 more nickels than dimes. How many quarters does Warren have?

Question 53619: Warren has 40 coins (all nickels, dimes, and quarters) worth $4.05. He has 7 more nickels than dimes. How many quarters does Warren have?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Warren has 40 coins (all nickels, dimes, and quarters) worth $4.05. He has 7 more nickels than dimes. How many quarters does Warren have?
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Let number of dimes be "x"; their value is 10x cents.
Number of nickels is "x+7"; their value is 5(x+7)=5x+35 cents
Number of quarters is "40-x-(x+7)" = "33-2x" ; their value is 25(33-2x)
=825-50x cents
EQUATION:
value + value = value
10x+5x+35+825-50x=405 cents
-35x=-45
x=13 (number of dimes)
x+7=20 (number of nickels)
33-2x=33-26=7 (number of quarters)
Cheers,
Stan H.

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