SOLUTION: Gordon figured that when he saved $21 more, he would have one-fourth of the money for the camera he wanted. How much does the camera cost if he had already saved one-sixth of the a

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Question 5308: Gordon figured that when he saved $21 more, he would have one-fourth of the money for the camera he wanted. How much does the camera cost if he had already saved one-sixth of the amount?
Answer by ichudov(499) About Me  (Show Source):
You can put this solution on YOUR website!
This problem is a problem of translating English into Algebrese.
Gordon figured that when he saved $21 more: saved+21
one-fourth of the money for the camera he wanted: camera_cost/4
he had already saved one-sixth of the amount: saved = camera_cost/6
You have two equations:
system%28+saved%2B21+=+camera_cost%2F4%2C%0D%0A+++++++++++saved+=+camera_cost%2F6+%29+
%0D%0A+system%28+saved+-+camera_cost%2F4+=+-21%2C%0D%0A+++++++++saved+-+camera_cost%2F6+=+0+%29+%0D%0A
%0D%0A+system%28+4%2Asaved+-+camera_cost+=+-84%2C%0D%0A+++++++++6%2Asaved+-+camera_cost+=+0+%29+%0D%0A
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
+system%28+%0D%0A++++4%5Csaved+%2B+-1%5Ccamera_cost+=+-84%2C%0D%0A++++6%5Csaved+%2B+-1%5Ccamera_cost+=+0+%29%0D%0A++

Any system of equations:
+system%28+%0D%0A++++a%5B11%5D%2Asaved+%2B+a%5B12%5D%2Acamera_cost+=+b%5B1%5D%2C%0D%0A++++a%5B21%5D%2Asaved+%2B+a%5B22%5D%2Acamera_cost+=+b%5B2%5D%29%0D%0A++

has solution
+system%28+%0D%0A++++saved+=+%28b%5B1%5D%2Aa%5B22%5D+-+b%5B2%5D%2Aa%5B12%5D%29%2F%28a%5B11%5D%2Aa%5B22%5D-a%5B21%5D%2Aa%5B12%5D%29%2C%0D%0A++++camera_cost+=+%28a%5B11%5D%2Ab%5B2%5D+-+a%5B21%5D%2Ab%5B1%5D%29%2F%28a%5B11%5D%2Aa%5B22%5D-a%5B21%5D%2Aa%5B12%5D%29%0D%0A++++%29%0D%0A++
or

+system%28+%0D%0A++++++saved+=+%28-84%2A-1+-+0%2A-1%29%2F%284%2A-1-6%2A-1%29+=+42%2C%0D%0A++++++camera_cost+=+%284%2A0+-+6%2A-84%29%2F%284%2A-1-6%2A-1%29+=+252%0D%0A++++%29%0D%0A++

(saved=42, camera_cost=252}