SOLUTION: The amount of a radioactive tracer remaining after t days is given A=Alower 0e^-0.058t, where A0 is the starting amount at the beginning of the time period. How many days will it t
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Question 47894: The amount of a radioactive tracer remaining after t days is given A=Alower 0e^-0.058t, where A0 is the starting amount at the beginning of the time period. How many days will it take for one-half of the orgininal amount to decay?
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
A0/2 = A0*e^(-0.058t)
1/2 = e^(-0.058t)
ln(1/2) = -0.058t
-ln(1/2)/0.058 = t
About 12 days
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