# SOLUTION: Doris invested some money at 7% and some money at 5% She invested 6,000 more at 5% than she did at 7% Her total yearly interest from the two investments was 600 How much did Doris

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Finance -> SOLUTION: Doris invested some money at 7% and some money at 5% She invested 6,000 more at 5% than she did at 7% Her total yearly interest from the two investments was 600 How much did Doris       Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Money, Business and Interest Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Money Word Problems Question 445047: Doris invested some money at 7% and some money at 5% She invested 6,000 more at 5% than she did at 7% Her total yearly interest from the two investments was 600 How much did Doris invest at each rate? Found 2 solutions by jorel1380, checkley79:Answer by jorel1380(2518)   (Show Source): You can put this solution on YOUR website!.07x+.05(x+6000)=600 7x+5(x+6000)=60000 7x+5x+30000=60000 12x=30000 x=30000/12=2500 x+6000=8500.. Answer by checkley79(3056)   (Show Source): You can put this solution on YOUR website!.07x+.05(x+6,000)=600 .07x+.05x+300=600 .12x=600-300 .12x=300 x=300/.12 x=\$2,500 amount invested @ 7%. 2,500+6,000=\$ 8,500 amount invested @ 5%. Proof: .07*2,500+.05*8,500=600 175+425=600 600=600