SOLUTION: A pay phone is holding a maximum number of 500 coins consisting of nickels, dimes and quarters. The number of quartes is twice the number of dimes.
If the value of all the coines
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Question 41837This question is from textbook
: A pay phone is holding a maximum number of 500 coins consisting of nickels, dimes and quarters. The number of quartes is twice the number of dimes.
If the value of all the coines is $88.00, how many nickles were in the pay phone?
This question is from textbook
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
Q+D+N=500 OR 2D+D+N=500 OR 3D+N=500 OR N=500-3D
25*2D+10D+5N=8800 SUB 500-3D FOR N & WE GET
50D+10D+5(500-3D)=8800 OR 60D+2500-15D=8800 OR 45D=6300 OR D=6300/45 OR D=140
140*10=1400 2D=280 OR 280*25=7000 & 500-140-280=80 OR 80*5=400
THUS 1400+7000+400=8800
THERE ARE 280 QUARTERS, 140 DIMES & 80 NICKLES.
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