SOLUTION: You are designing a house with three 3-feet-wide windows on the back of the house. There are 4 feet between each end window and an edge of the house. The width of the house is 33
Algebra.Com
Question 369838: You are designing a house with three 3-feet-wide windows on the back of the house. There are 4 feet between each end window and an edge of the house. The width of the house is 33 feet. How far apart should the windows be?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Subtract the 4 feet from each end, 33 minus 8 leaves 25. You want to evenly distribute 3 times 3' = 9 feet of window into a space 25 feet wide. 25 minus 9 is 16. 16 has to be divided evenly between the two spaces on either side of the center window. 8 feet.
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
How do you wright an equation for this problem?:
You are designing a house with three... (answered by josmiceli)
A rectangular front of a house measures 15 feet by 29 feet. A rectangular door on the... (answered by solver91311)
You are planning to paint a house. A) How many square feet will you need to paint? (there (answered by addingup)
I hope someone can help me.Thank you in advance.
A Norman window is a rectangle with a (answered by Alan3354,edjones)
A house has 3 windows that are polygons with a total of 13 sides. Two of the windows are... (answered by macston)
A wall that is 12 feet wide and 8 feet high must be painted. There are 2 windows... (answered by checkley75)
"a contractor is designing one side of one-story office building to be 70 feet in... (answered by rothauserc)
Phillip’s bedroom is 15 feet by 16 feet with an 8-foot ceiling. There are two windows... (answered by mananth)
A contractor is going to paint the room shown above. The paint costs $28.03 a gallon. One (answered by Theo)
