SOLUTION: what quantity x maximizes revenue? What is the maximum revenue? P=-1/6x+100 0<=x<=600

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Question 359735: what quantity x maximizes revenue? What is the maximum revenue?
P=-1/6x+100 0<=x<=600
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
P=-%281%2F6%29x%2B100+ is maximimized with the smallest x (x=0).
P%5Bmax%5D=0%2B100
P%5Bmax%5D=100
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