SOLUTION: Bob owns a watch shop. He is open 5 days a week. he has figured out over the years that the cost of operating his his shop is C(x)=2x^2-57+26 where x is the number of watches repai

Question 359689: Bob owns a watch shop. He is open 5 days a week. he has figured out over the years that the cost of operating his his shop is C(x)=2x^2-57+26 where x is the number of watches repaired. What is the daily cost of running the shop if the number of watches repaired is 50?
I think the problem begins by putting 250 in for a week and 50 in for a day.
C(250)=2(250)^2-57(250)+26 but I'm not sure and this is really proving difficult for me. I am trying hard to understand this and I am trying to get ready for an algebra class that starts in January. I am trying to learn as much as I can before I got to help ease the anxiety.
Thanks
Sally (Soon to be in college)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Bob owns a watch shop. He is open 5 days a week. he has figured out over the years that the cost of operating his his shop is C(x)=2x^2-57+26 where x is the number of watches repaired. What is the daily cost of running the shop if the number of watches repaired is 50?
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It's not specified that the cost is per day, per week, or what.
The only number given is 50, and it asks for the cost per day. That implies that it's a daily cost.
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Sub 50 for x and find C
C(x)=2x^2-57+26
C(50) = 2*50^2 -57 + 26 (should that be 57x ?)
C(50) = 2500 - 57 + 26
C(50 = 2469
It's not clear if that's $2469, or $24.69 either.
Poorly written problem.

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