SOLUTION: Janet invested $26,000 part at 6% and part at 3%, if the total interest at the end of the year is $1,080, how much did she invest at 6%?

SOLUTION: Janet invested $26,000 part at 6% and part at 3%, if the total interest at the end of the year is $1,080, how much did she invest at 6%?

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Question 351052: Janet invested $26,000 part at 6% and part at 3%, if the total interest at the end of the year is $1,080, how much did she invest at 6%?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
$26,000 total investment
6% ------------$x
3%, ------------26000-x
interest =$1,080,
...
0.06x+0.03(26000-x)=1080
multiply by 100
6x +3(26000-x)=108000
6x+78000-3x=108000
3x=108000-78000
3x=30000
x= $10000 @ 6%
$16000 @ 3%
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