SOLUTION: A man made a profit of P 290 by selling 8 cows and 14 calves at a gain of 25% of what they cost him. Had he sold 14 cows and 8 calves instead at the same percentage of profit, he w
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Question 347475:  A man made a profit of P 290 by selling 8 cows and 14 calves at a gain of 25% of what they cost him. Had he sold 14 cows and 8 calves instead at the same percentage of profit, he would have gained P400. Find the original cost of each cow and each calf? 
Answer by nyc_function(2741)   (Show Source): You can put this solution on YOUR website!
 Let X = Cost of Cows
Let Y= Cost of Claves
=> 1/4 ( 8X + 14Y ) = 290
=> 8X + 14Y = 1160 ---------- A
=> 1/4 ( 14X + 8Y ) = 400
=> 14X + 8Y = 1600 ----------- B
=> Now try to eliminate one of the unknow values by using common factors
=> Multiply A by 4 
=> 4 (8X + 14Y = 4 (1160 ) 
=> 32X + 56Y = 4640 --------- C
=> Multiply B by 7
=> 7 (14X + 8Y) = 7 (1600) 
=> 98X + 56Y = 11200 ------- D
=> D - C
=> ( 98X + 56Y ) - ( 32X + 56Y ) = 11200 - 4640
=> 66X = 6560
=> X = 99.393939......
=> X = 99.40
=> Sub. X = 99.40 into A or any equations from above
=> 8X + 14Y = 1160 
=> 8 (99.40) + 14Y = 1160
=> 795.20 + 14Y = 1160
=> 14Y = 1160 - 795.20
=> 14Y = 364.80
=> Y = 364.8 / 14
=> Y = 26.05714...
=> Y = 26.06
Answer: Original Cost for Cows $99.40 each, $26.06 for Calves each.
 
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