SOLUTION: A total of 4000 was invested,part of it at 8% interest and the remainder at 9%. if the total yearly interest amounted to $ 350, how much was invested at each rate
Algebra.Com
Question 342172: A total of 4000 was invested,part of it at 8% interest and the remainder at 9%. if the total yearly interest amounted to $ 350, how much was invested at each rate
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
let x = amount invested at 8%
let y = amount invested at 9%
x+y=4000
.08x+.09y=350
x=4000-y
.08(4000-y)+.09y=350
320-.08y+.09y=350
.01y=30
y=3000
x=1000
RELATED QUESTIONS
A total of $4000 was invested, part of it at 8% interest and the remainder at 9%. If the... (answered by checkley77)
A total of $4000 was invested, part of it at 8% interest and the remainder at 9%. If the (answered by ewatrrr)
A total of $4000 was invested, part of it at 8% and the remainder at 9%. If the total... (answered by jojo14344)
A total of $3900 was invested, part of it at 8% interest and the remainder at 13%. If the (answered by mananth)
a total of $4300 was invested, part of it at 8% and the remainder at 13%. if the total... (answered by josgarithmetic)
a total of 3500 was invested, part of it at 8% interest and the remainder at 13%. if the... (answered by richwmiller)
A total of $4300 was invested, part of it at 5% interest and the remainder at 10%. If the (answered by mananth)
A total of $4500 was invested, part of it at 6% interest and the remainder at 12%. If the (answered by subudear)
A total of $3700 was invested, part of it at 6% interest and the remainder at 11%. If the (answered by mananth)