SOLUTION: A woman has invested money in two accounts. Part of the money is invested in an account paying 7% interest, and twice that amount is invested in an account paying 9% interest. Aft

Question 326710: A woman has invested money in two accounts. Part of the money is invested in an account paying 7%
interest, and twice that amount is invested in an account paying 9% interest. After one year, the total
interest on the two investments is $500. How much did the woman invest at each rate?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
account paying 7% let the amount invested be x
twice that amount account paying 9% = 2x
interest after one year,= $500.
..
0.07x +0.09*2x=500
0.07x+0.18x=500
0.25x=500
divide by 0.25
0.25x/0.25 = 500/0.25
x= 500/0.25
=$ 2000 at 7%
2x = 2*2000 = $4000 at9%
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