SOLUTION: Please help me!!! A jazz group on tour has been drawing average crowds of 500 persons. It is projected that for every $1 increase in the $12 ticket price, the average attendance wi

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Question 30720: Please help me!!! A jazz group on tour has been drawing average crowds of 500 persons. It is projected that for every $1 increase in the $12 ticket price, the average attendance will decrease by 50. At what ticket price will the nightly receipts be $5600?
Found 2 solutions by Paul, AnlytcPhil:
Answer by Paul(988)   (Show Source): You can put this solution on YOUR website!
Let x be the number of $1 increase:
Cost of tickets: x+12
Tickets sold = 500-50x
Equation:
(x+12)(500-50x)=5600



Multiply the whole equation by -1 to remove the negative and simplfy:


Use the quadratic formula:

a=1, b=2, c=-8


or
Remove the negative: and simplfy to get:
x=2
12+2=14
Hence, it will be $14.
Paul.

Answer by AnlytcPhil(1806)   (Show Source): You can put this solution on YOUR website!
Please help me!!! A jazz group on tour has been drawing average crowds of 500
persons. It is projected that for every $1 increase in the $12 ticket price,
the average attendance will decrease by 50. At what ticket price will the
nightly receipts be $5600?

Let x = the number of $1 increases in price

Let y = the nightly receipts

Then the price per ticket will be $(12 + x)

and so the number attending will be 500 - 50x

Nightly receipt = (Price per ticket)×(the number of attendees) =

              y = (12 + x)(500 - 50x)

So we substitute 5600 for y.

            5600 = (12 + x)(500 - 50x)

Can you solve this? If not post again. 

There are two solutions, x = -4 and x = 2

Choose the positive answer, discard the negative one.

Check:

When there are 2 $1 tickets the price per ticket is $14 
There were 500 - 2(50) = 400 attendees.
The intake is $14 times 400 or $5600

Edwin
AnlytcPhil@aol.com


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