SOLUTION: a total of $10000 was invested in to simple intrest accounts for one year. the first account has an 8% intrest rate, the second account has a 9% intrest rate. if the total intrest

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Finance -> SOLUTION: a total of $10000 was invested in to simple intrest accounts for one year. the first account has an 8% intrest rate, the second account has a 9% intrest rate. if the total intrest       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 301736: a total of $10000 was invested in to simple intrest accounts for one year. the first account has an 8% intrest rate, the second account has a 9% intrest rate. if the total intrest of the 2 accounts in one year was $840 how much was invested in each account
Answer by JBarnum(2044) About Me  (Show Source):
You can put this solution on YOUR website!
F%2BS=10000 F=amount of money invested in First account, S=amount of money invested in Second account
.08F%2B.09S=840 8%=.08 9%=.09
u can use substitution or elimination method i will use elimination method as its faster.
F%2BS=10000 multiply this by -.08
.08F%2B.09S=840
_________________
-.08F-.08S=-800
.08F%2B.09S=840add the equations together
.01S=40
S=4000
_______
F%2BS=10000
F%2B4000=10000
F=6000
first account has 6000
second account has 4000