SOLUTION: Adult tickets for a play cost $15 and child tickets cost $1. If there were 29 people at a performance and the theater collected $155 from ticket sales, how many adults and how man

Question 29140: Adult tickets for a play cost $15 and child tickets cost $1. If there were 29 people at a performance and the theater collected $155 from ticket sales, how many adults and how many children attended the play?
Found 2 solutions by checkley72, atif.muhammad:
Answer by checkley72(6) (Show Source): You can put this solution on YOUR website!
$15.00 X Adults + $1.00 X Children = $ 155.00
Adults + Children = 29 Or (A + C = 29)
A + C = 29 C = 29 - A
Substituting C = 29 - A in the first equation & solving for A we get:
15A + 1(29 - A)= 155
15A + 29 - A = 155
15A - A = 155 - 29
14 A = 126
A = 126/14 or A = 9.
A + C = 29 or 9 + C = 29 or C = 29 - 9 or C = 20.
9 Adults @ $ 15.00 + 20 Children @ $ 1.00. $ 135.00 + $ 20.00 = $ 155.00
9 Adults + 20 Children = 29 people attending the play.

Answer by atif.muhammad(135) (Show Source): You can put this solution on YOUR website!
Let the number of adults = x and children = y
The total number of people at the performance were 29, therefore, x+y=29
The total amount of money collected was $155, therefore, 15x + y = 155
Therefore, we now have a pair of simultaneous equations:
x+y=29 --> 1
15x+y=155 --> 2
Manipulate 1.
x+y=29
y=29-x --> 3
Substitute 3 into 2:
15x + 29 - x = 155
14x = 126
x=9

y=29-x = 29-9 = 20
x=9, y=20

number of adults = 9
number of children = 20
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