# SOLUTION: A person invested a sum of money at 9% annual simple interest and invested twice that amount at 11% annual simple interest. If the total yearly income from both investments was \$1,

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 Question 268140: A person invested a sum of money at 9% annual simple interest and invested twice that amount at 11% annual simple interest. If the total yearly income from both investments was \$1,395 how much was invested at each rate? Thank you for your help. It's greatly appreciated.Answer by ankor@dixie-net.com(15622)   (Show Source): You can put this solution on YOUR website!A person invested a sum of money at 9% annual simple interest and invested twice that amount at 11% annual simple interest. If the total yearly income from both investments was \$1,395 how much was invested at each rate? : Let x = amt invested at 9% then 2x = amt invested at 11% : a total interest equation .09x + .11(2x) = 1395 : .09x + .22x = 1395 : .31x = 1395 x = x = \$4500 invested at 9% and, obviously: 2(4500) = \$9000 invested at 11% : : Check this by finding the total interest with these values: .09(4500) + .11(9000) = 405 + 990 = 1395