SOLUTION: A person invested a sum of money at 9% annual simple interest and invested twice that amount at 11% annual simple interest. If the total yearly income from both investments was $1,

Question 268140: A person invested a sum of money at 9% annual simple interest and invested twice that amount at 11% annual simple interest. If the total yearly income from both investments was $1,395 how much was invested at each rate?
Thank you for your help. It's greatly appreciated.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A person invested a sum of money at 9% annual simple interest and invested twice that amount at 11% annual simple interest.
If the total yearly income from both investments was $1,395 how much was invested at each rate?
:
Let x = amt invested at 9%
then
2x = amt invested at 11%
:
a total interest equation
.09x + .11(2x) = 1395
:
.09x + .22x = 1395
:
.31x = 1395
x =
x = $4500 invested at 9%
and, obviously:
2(4500) = $9000 invested at 11%
:
:
Check this by finding the total interest with these values:
.09(4500) + .11(9000) =
405 + 990 = 1395
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