SOLUTION: A sum of $113,000 is split between two investments, one paying 6% and the other 9%. If the total yearly interest amounted to $8550, how much was invested at 9%?
Algebra.Com
Question 261635: A sum of $113,000 is split between two investments, one paying 6% and the other 9%. If the total yearly interest amounted to $8550, how much was invested at 9%?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.09X+.06(113,000-X)=8,550
.09X+6,780-.06X=8,550
.03X=8,550-6,780
.03X=1,770
X=1,770/.03
X=59,000 ANS. FOR THE AMOUNT INVESTED @ 9%.
113,000-59,000=54,000
.09*59,000+.06*54,000=8,550
5,310+3,240=8,550
8,550=8,550
RELATED QUESTIONS
A sum of $3500 is split between two investments, one paying 9% yearly interest and the... (answered by checkley75)
$740 is split into two investments, one paying 6% and the other paying %9 interest. if... (answered by macston)
a sum of rs 2000 is split between two investments, one paying 7% interest and the other... (answered by mananth)
A sum of $2000 is split between two investments, one paying 7% interest and the other 8%. (answered by josmiceli)
Jackson has investments totaling K8, 000 in two accounts – one a savings account paying
(answered by jorel555)
Solve the problems in one variable.
A company decided to invest P100, 000 which was... (answered by greenestamps)
Jessica has half of her investments in stock paying a 6% dividend and the other half in a (answered by ikleyn)
a total of $25000 is invested in two funds paying 6% and 8.5% simple interest. the 6%... (answered by stanbon,scott8148)
A woman had two investments, one paying a 6% dividend. The other is $680 more than half... (answered by ikleyn)