# SOLUTION: A woman invested part of 20,000 at 6% and the rest at 7%. If her annual interest is 1,260, how much did she invest at 6%? Interest problems always stump me. Any help with this c

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 Question 25741: A woman invested part of 20,000 at 6% and the rest at 7%. If her annual interest is 1,260, how much did she invest at 6%? Interest problems always stump me. Any help with this could really help me.Answer by elima(1433)   (Show Source): You can put this solution on YOUR website!The formula for interest; I=prt I=interest p=principal r=rate t=time So you are given everything except p; I=1260 r=7% t=1 So, with those amounts we solve for p; 1260=p(.07)1 multiply (.07)1; 1260=p(.07) Now divide each side by (.07) = 18,000=p So \$18,000 was invested at 7%, so \$20,000-\$18,000=\$2,000 at 6% \$2,000 was invested Hope you understand =)