# SOLUTION: the cost of labor for producing x transmissions is L(x) = 0.3x^2 + 400x + 550 dollars, while the cost of materials is M(x) = 0.1x^2 + 50x + 800 dollars. write a polynomial T(x) tha

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Finance -> SOLUTION: the cost of labor for producing x transmissions is L(x) = 0.3x^2 + 400x + 550 dollars, while the cost of materials is M(x) = 0.1x^2 + 50x + 800 dollars. write a polynomial T(x) tha      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Word Problems: Money, Business and Interest Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Money Word Problems Question 257333: the cost of labor for producing x transmissions is L(x) = 0.3x^2 + 400x + 550 dollars, while the cost of materials is M(x) = 0.1x^2 + 50x + 800 dollars. write a polynomial T(x) that represents the total cost of materials and labor for producing x transmissions.Answer by drk(1908)   (Show Source): You can put this solution on YOUR website!Total cost of labor and materials is addition. So, L(x) + M(x) = T(x). We can express that as combining like terms gets us