SOLUTION: A music dealer ran a sale of records and tapes. Records were sold at $7 each and tapes at $7.50 each. The dealer sold 60 more records than tapes for a total of $2160. How many rec

Question 255354: A music dealer ran a sale of records and tapes. Records were sold at $7 each and tapes at $7.50 each. The dealer sold 60 more records than tapes for a total of $2160. How many records did the dealer sell?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
R=T+60
7R+7.50T=2,160
REPLACE R WITH (T+60 IN THE SECOND EQUATION & SOLVE FOR T.
7(T+60)+7.50T=2,160
7T+420+7.50T=2,160
14.50T=2,160-420
14.50T=1,740
T=1,740/14.50
T=120 IS THE NUMBER OF TAPES SOLD.
R=120+60=180 RECORDS WERE SOLD.
PROOF:
7*180+7.50*120=2,160
1,260+900=2,160
2,160=2,160
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