SOLUTION: Colin invested 10,000, part at 14% and part at 17%. If the total interest at the end of the year is 1,490, how much did he invest at 14%?

Algebra.Com
Question 243339: Colin invested 10,000, part at 14% and part at 17%. If the total interest at the end of the year is 1,490, how much did he invest at 14%?
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
.14x+.17(10,000-x)=1,490
.14x+1,700-.17x=1,490
-.03x=1,490-1,700
-.03x=-210
x=210/.03
x=$7,000 invested @ 14%.
10,000-7,000=3,000 invested @ 17% Proof:
.14*7,000+.17*3,000=1,490
980+510=1,490
1,490=1,490

RELATED QUESTIONS

Stan invested $5,000, part at 8% and part at 17%. If the total interest at the end of the (answered by stanbon)
Stan invested $5,000, part at 8% and part at 17%. If the total interest at the end of... (answered by Hook)
24. Stan invested $5,000, part at 8% and part at 17%. If the total interest at the end... (answered by checkley71)
Stan invested $5,000, part at 8% and part at 17%. If the total interest at the end of... (answered by checkley71)
Stan invested $5,000, part at 8% and part at 17%. If the total interest at the end of... (answered by checkley75,bucky)
Stan invested $5,000, part at 8% and part at 17%. If the total interest at the end of... (answered by Caallen2)
Colin invested $24,000, part at 18% and part at 16%. If the total interest at the end of... (answered by checkley71,Nate)
Colin invested $37,000, part at 16% and part at 3%. If the total interest at the end of... (answered by checkley71,tutorcecilia)
Colin invested $32,000, part at 8% and part at 12%. If the total interest at the end of... (answered by checkley77,oscargut)