SOLUTION: a triangle has a perimeter of 54 inches. find the length of the three sides if one side is 10 inches longer than the smallest and the third side is twice the smallest.

Question 238264: a triangle has a perimeter of 54 inches. find the length of the three sides if one side is 10 inches longer than the smallest and the third side is twice the smallest.
Found 2 solutions by alicealc, stanbon:
Answer by alicealc(293) (Show Source): You can put this solution on YOUR website!
first side (smallest) = x
second side = 10 + x
third side = 2x

perimeter = 54
x + 10 + x + 2x =54
4x + 10 = 54
4x = 54 - 10
4x = 44
x = 44/4
x = 11

so, the three sides of the triangle will be: 11 inches, 21 inches,and 22 inches
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a triangle has a perimeter of 54 inches. find the length of the three sides if one side is 10 inches longer than the smallest and the third side is twice the smallest.
----------------------
Let the smallest be "x".
The 2nd side is "x+10"
The 3rd side is "2x"
----------------------------
Equation:
x + x+10 + 2x = 54
4x + 10 = 54
4x = 44
x = 11
---------------
smallest = 11 inches
2nd = 11+10 = 21 inches
3rd = 2x = 22 inches
===================================
Cheers,
Stan H.
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