# SOLUTION: Hi could I please have help with this: A basketball team sells tickets that cost \$10, \$20, or, for VIP seats, \$30. The team has sold 517 tickets overall. It has sold 216 more \$2

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 Click here to see ALL problems on Money Word Problems Question 22972: Hi could I please have help with this: A basketball team sells tickets that cost \$10, \$20, or, for VIP seats, \$30. The team has sold 517 tickets overall. It has sold 216 more \$20 tickets than \$10 tickets. The total sales are \$9690. How many tickets of each kind have been sold? How many \$10 tickets were sold? How many \$20 tickets were sold? How many \$30 tickets were sold? thank you.Answer by stanbon!(97)   (Show Source): You can put this solution on YOUR website!Let the number of \$10 tickets be "x" Then the number of \$20 tickets is x+216. Since the total sold is 517 the number of \$30 tickets is 517-(x+x+216)= 301-2x Value of \$10 tickets is (10)x dollars Value of \$20 tickets is (20)(x+216)=(20x+4320)dollars Value of \$30 tickets is (30)(301-2x)= (9030-60x)dollars EQUATION: Value of 10's + Value of 20's + Value of 30's is 9690 dollars 10x + 20x+4320 +9030-60x = 9690 -30x = -3660 x = 122 (number of \$10 tickets) x+216 = 338 (number of \$20 tickets) 301-2x = 57 (number of \$30 tickets) Cheers, Stan H.