SOLUTION: OK!! I WOULD LOVE IT IF U WOULD HELP ME WITH THIS PROBLEM BECUASE I AM SO CONFUSED ADN I DONT EVEN KNOW WHERE TO START! I HAVE TO WRITE AN ALGEBRAIC EQUATION FOR THIS PROBLEM! MS.

Question 21830: OK!! I WOULD LOVE IT IF U WOULD HELP ME WITH THIS PROBLEM BECUASE I AM SO CONFUSED ADN I DONT EVEN KNOW WHERE TO START! I HAVE TO WRITE AN ALGEBRAIC EQUATION FOR THIS PROBLEM! MS.SPEEDI KEEPS COINS FOR PAYING THE TOLL CROSSINGS ON HER COMMUTE TO AND FROM WORK.SHE PRESENTLY HAS THREE MORE DIMES THAN NICKELS ADN TWO FEWER QUATERS THEN NICKELS. THE TOTAL VALUE IF $5.40. FIND THE NUMBER OF EACH TYPE FO COIN SHE HAS!! IT WOULD BE A BIGH HELP IF I HAD HELP ON THIS THANK U
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Let number of nickels be "x"
Then number of dimes is "x+3"
And number of quarters is "x-2"
Value of nickels is 5x cents
Value of dimes is 10(x+3)= 10x+30 cents
Value of quarters is 25(x-2)=25x-50 cents
EQUATION:
Value of nickels + Value of dimes + Value of quarters is 540 cents
5x +10x+30 +25x-50 = 540
40x = 560
x = 14 (number of nickels)
x+3 = 17 (number of dimes)
x-2 = 12 (number of quarters)
Cheers,
Stan H.

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