SOLUTION: Pat invested a total of $3,000. Part of the money yields 10 percent interest per year, and the rest yields 8 percent interest per year If the total yearly interest from the this i
Algebra.Com
Question 211106This question is from textbook ETS GRE
: Pat invested a total of $3,000. Part of the money yields 10 percent interest per year, and the rest yields 8 percent interest per year If the total yearly interest from the this investment is $256, how much did Pat invest at 10 percent and how much at 8 percent?
This question is from textbook ETS GRE
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.10x+.08(3,000-x)=256
.10x+240-.08x=256
.02x=256-240
.02x=16
x=16/.02
x=800 amount invested @ 10%
3,000-800=2,200 invested @ 8%
Proof:
.10*800+.08*2,200=256
80+176=256
256=256
RELATED QUESTIONS
1. Pat invested a total of $3000. Part of the money yields 10 percent interest per year, (answered by scott8148)
Please help me solve this equation: Pat... (answered by jim_thompson5910,Mathtut)
Pat invested a total of $3,000. Part of the money yields 10 percent interest per year and (answered by checkley77)
Pat invested a total of $3,000. Part of the money yields 10 percent interest per year,... (answered by ptaylor)
Pat invested a total of $3000. Part of the money yields 10% interest per year and the... (answered by stanbon)
Hi,
Here's another GRE math test prep word problem that has me stumped. I can't find the (answered by Mathtut)
Pat invested $3K. part of the money was invested in an account that paid 10 percent... (answered by richwmiller)
If money is invested at r percent interest, compounded annually, the amount of the... (answered by Theo)
Walt made an extra $10,000 last year from a part-time job. He invested part of the money... (answered by ikleyn,greenestamps)