SOLUTION: Please solve this word problem, thank you SO much! There were 22 more nickels than dimes in Danny's bag. If there were 50 coins total, how many nickels were there?

Question 206490This question is from textbook Algeba I: An Incremental Development
: Please solve this word problem, thank you SO much!
There were 22 more nickels than dimes in Danny's bag. If there were 50 coins total, how many nickels were there? This question is from textbook Algeba I: An Incremental Development

Found 2 solutions by rfer, dyakobovitch:
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
nickels=d+22=36
dimes=d=14
--------------
d+22+d=50
2d+22=50
subtract 22 form both sides
2d=28
divide both sides by 2
d=14

Answer by dyakobovitch(40) (Show Source): You can put this solution on YOUR website!
Let dimes=x.
Let nickles = x+22.

So, 50 = x + x + 22 = 2x + 22
28=2x
14=x
So, you have 14 + 22 or 36 nickels.

Feel free to leave comments with any questions or concerns. -- David
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