SOLUTION: An airline has 2000 passengers each day paying $100 each, and knows that for each $10 increase in price they lose 50 passengers. What would be the equation that would determine th

Algebra.Com
Question 199: An airline has 2000 passengers each day paying $100 each, and knows that for each $10 increase in price they lose 50 passengers. What would be the equation that would determine their maximum revenue?
Answer by ichudov(507)   (Show Source): You can put this solution on YOUR website!
Airline's revenue is: Number of passengers * ticket price.

Number of passengers also depends on ticket price:

Number of passengers = 2,000 - 50 * (ticket price - 100)/10

So, airline's revenue is:

(2,000 - 50 * (ticket price - 100)/10)*ticket price

Denote ticket price as x

Revenue = (2000-50*(x-100)/10)*x

When you simplify it, you get a quadratic expression, that you can plot on my site.

RELATED QUESTIONS

A transit company has 500 passengers daily, each currently paying a $2.25 fare. For each... (answered by ankor@dixie-net.com)
A bus company has 4000 passengers daily, each paying a fare of $2. For each $0.15... (answered by ankor@dixie-net.com)
A bus company has 4000 passengers daily, each paying a fee of 2$. For each 0.15$... (answered by ankor@dixie-net.com)
A bus company has 3,000 passengers daily, paying a $1.25 fare. For each 25¢ increase in... (answered by Edwin McCravy)
An airline transports about 800 people between Chicago and New York. A round-trip ticket... (answered by stanbon)
A bus company has 4000 passengers daily, each paying a fare of $2. For each $.015... (answered by ankor@dixie-net.com)
A bus company has 4000 passengers daily, each paying a fare of $2. For each $0.15... (answered by ankor@dixie-net.com)
A bus company has 4000 passengers daily, each paying a fare of $2. For each $0.15... (answered by ankor@dixie-net.com)
In a local arena, there are 1000 premium seats, costing $50 each. Due to an increase in... (answered by robertb)