SOLUTION: Joe invested a portion of $6000 at 4.5% interest and the balance at 6% interest. How much did he invest at each rate if his total income from both investments is $279?
Algebra.Com
Question 196351: Joe invested a portion of $6000 at 4.5% interest and the balance at 6% interest. How much did he invest at each rate if his total income from both investments is $279?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.06x+.045(6,000-x)=279
.06x+270-.045x=279
.015x=279-270
x=9/.015
x=600
6,000-600=5,400
.06*600+.045*5,400=279
36+243=279
279=279
RELATED QUESTIONS
Joe invested a portion of $6000 at 4.5% interest and the balance at 6% interest. How much (answered by checkley77)
Alex invested $6000, part at 6% simple interest and part at 4% simple interest for a... (answered by mananth)
Joe invests $6000, part at 5% interest and the rest at 7%. If his annual interest income... (answered by mananth)
John invested a portion of 15,000 at 10 percent annual interest rate and the balance at 6 (answered by richwmiller)
A man invested $6000, part of it at 5% simple interest and the rest at 7% simple... (answered by checkley71)
a man invested $6000, part of it at 5%simple interest and the rest at 7% simple interest. (answered by checkley77)
A man invested $6000, part of it at 5% simple interest and the rest at 7% simple... (answered by checkley77)
A man invested $6000, part of it at 5% simple interest and the rest at 7% simple... (answered by checkley77)
Sally invested $6000, part at %6 simple interest and a part at 4% simple interest for a... (answered by richwmiller)