SOLUTION: Mark has 56 coins totalling $7.10. If he has only dimes and quarters, how many of each coin does he have?
Algebra.Com
Question 189313: Mark has 56 coins totalling $7.10. If he has only dimes and quarters, how many of each coin does he have?
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
Q+D=56 OR Q=56-D
.25Q+.10D=7.10
.25(56-D)+.10D=7.10
14-.25D+.10D=7.10
-.15D=7.10-14
-.15D=-6.90
D=-6.90/-.15
D=46 IS THE NUMBER OF DIMES.
56-46=10 IS THE NUMBER OF QUARTERS.
PROOF:
.25*10+.10*46=7.10
2.50+4.60=7.10
7.10=7.10
RELATED QUESTIONS
Bob has 26 coins totalling $2.15. If he has only nickels and dimes, how many of each coin (answered by Mathtut)
Bob has 31 coins totalling $2.50. If he has only nickels and dimes, how many of each coin (answered by Alan3354)
If roger has 43 coins consisting of only dimes and quarters and in total he has 6.55$ How (answered by ankor@dixie-net.com)
John has 27 coins totaling $5.70. If he only has dimes and quarters, how many of each... (answered by josmiceli)
john has 20 coins totaling $3.20. if he has only dimes and quarters how many of each coin (answered by josgarithmetic)
Keegan has 10 coins in his pocket that total $2.05. He only has quarters and dimes. How... (answered by ewatrrr)
Bon has 18 coins. If he has $3.45 and only quarters and dimes, how many of each does he... (answered by checkley77)
mark has 42 coins consisting of dimes and quarters. the total value of his coins is $6.... (answered by lynnlo)
Luke has 21 coins worth $3.90. If he has only dimes and quarters, how many of each does... (answered by josmiceli)