SOLUTION: Sam found a number of nickels,dimes, and quarters in his room. He found three more dimes than nickels, but twice as many quarters as dimes. The total value of the coins was $5.05.

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Let = the number of nickels he found
Let = the number of dimes he found
Let = the number of quarters he found
given:
(1)
(2)
(3) (this is in pennies)
Substitute (1) and (2) in (3)
(3)
(3)
(3)
(3)
Substitute (1) in (3)
(3)
(3)
(3)
(3)
Plug this back into (1)
(1)
(1)
(1)
And from (2)
(2)
(2)
Sam found 5 nickels, 8 dimes, and 16 quarters
check:
(1)


(2)


(3)



OK

You can put this solution on YOUR website!

Sam found a N nickels, D dimes, and Q quarters in his room. He found three more
dimes than nickels (D = N+3), but twice as many quarters as dimes (Q=2D). The
total value of the coins was $5.05 (5N + 10D + 25Q = 505). How many coins of
each type did Sam find? Please show me the steps you took to get your answer;
I am totally lost!

Edwin's solution:



Can you solve that system? If not post again, asking how.

Answer: 5 Nickels, 8 Dimes, 16 Quarters

Edwin