SOLUTION: Jim has a total of 50 coins. Some are nickels and some are dimes. Altogether he has $4.15. How many dimes does he have? How many Nickels? show your work using algebra and the fiv s

Question 173671: Jim has a total of 50 coins. Some are nickels and some are dimes. Altogether he has $4.15. How many dimes does he have? How many Nickels? show your work using algebra and the fiv step method.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
D+N=50 OR D=50-N
.10D+.05N=4.15
.10(50-N)+.05N=4.15
5-.10N+.05N=4.15
-.05N=4.15-5
.05N=.85
N=.8/.05
N=17 IS THE NUMBER OF NICKLES.
50-17=33 NUMBER OF DIMES.
PROOF:
.10*33+.05*17=4.15
3.30+.85=4.15
4.15=4.15

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