SOLUTION: How many gallons of 30% alcohol must be mixed with 60 gallons of 14% alcohol to obtain a solution that is 20% alcohol?
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Question 168783: How many gallons of 30% alcohol must be mixed with 60 gallons of 14% alcohol to obtain a solution that is 20% alcohol?
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
let A= # of gallons of 30% solution of alcohol
.3A+60(.14)=.2(60+A)
.3A+8.4=12+.2A----->subtract .2A and 8.4 from each side
:
.1A=3.6
:
gallons of 30% solution of alcohol
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