SOLUTION: Investing. A man invested $14,000, some at 7% and some at 10% annual interest. The annual income from these investments was $1,280. How much did e invest at each rate?
Algebra.Com
Question 155493This question is from textbook Intermediate Algebra
: Investing. A man invested $14,000, some at 7% and some at 10% annual interest. The annual income from these investments was $1,280. How much did e invest at each rate?
This question is from textbook Intermediate Algebra
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.10x+.07(14,000-x)=1,280
.10x+980-.07x=1,280
.03x=1,280-980
.03x=300
x=300/.03
x=10,000 invested @ 10%
14,000-10,000=4,000 invested @ 7%
Proof:
.10*10,000+.07*4,000=1,280
1,000+280=1,280
1,280=1,280
RELATED QUESTIONS
Part of a $8, 000 inheritance was invested at 10% interest and the rest was in- vested at (answered by stanbon)
a man invested $20,000 at annual interest rate of 7% and $12,000.00 at an annual interest (answered by stanbon)
Roberto invested some money at 7%, and then invested $2000 more than twice this amount... (answered by Nate)
Roberto invested some money at 7%, and then invested $2000 more than twice this amount at (answered by mananth,checkley77)
Lucy has some money invested at 18% annual interest and three times as much invested at... (answered by josmiceli)
Part of $6,000 was invested at 10% interest and the rest at 12%. If the annual income... (answered by greenestamps)
A MAN INVESTED $20.000 at an annual interest rate of 7% and $ 12,000.00 at an annual... (answered by calegebra)
A man has invested $8000, part of 10% and the remainder at 6% simple interest. how much... (answered by mananth)
How do you solve the problem of split investments? A man investing $12,000, part at 7%... (answered by ankor@dixie-net.com)