SOLUTION: A plumber and his assistant work together to replace the pipes in an old house. The plumber charges $45 an hour for his own labor and $25 an hour for his assistant's labor. The p
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Question 154978This question is from textbook
: A plumber and his assistant work together to replace the pipes in an old house. The plumber charges $45 an hour for his own labor and $25 an hour for his assistant's labor. The plumber works twice as long as his assistant labor on this job, and the labor charge on the final bill is $4025. How long did the plumber and his assistant work on this job?
This question is from textbook
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
Let p=plumber's time and a=assistants time
p=2a
45p+25a=4025
(45*2a)+25a=4025 Substitute.
90a+25a=4025
115a=4025
a=4025/115
=35hrs
p=70hrs
.
Ed
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