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Question 147636: For a sample of size n = 100, proportion p = 0.6, and at a 95% confidence level, the upper bound of the portion is:: For a sample of size n = 100, proportion p = 0.6, and at a 95% confidence level, the upper bound of the portion is:
Answer by stanbon(17786) About Me  (Show Source):
You can put this solution on YOUR website!
For a sample of size n = 100, sample proportion p = 0.6, and at a 95% confidence level, the upper bound of p is:
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E = 1.96sqrt[(0.6)(0.4)/100]
E = 1.96sqrt[0.04899)
E = 0.09602
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Upper bound of the 95% CI is 0.6+0.09602 = 0.69602..
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Cheers,
Stan H.