SOLUTION: A coffee manufacturer wants to market a new blend of coffee that sells for $3.90 per pound by mixing two coffees that sell for $2.75 and $5.00 per pound, respectively. What amounts
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Question 146153This question is from textbook New Mexico Edition College Algebra
: A coffee manufacturer wants to market a new blend of coffee that sells for $3.90 per pound by mixing two coffees that sell for $2.75 and $5.00 per pound, respectively. What amounts of each coffee should be blended to obtain the desired mixture? [Hint: Assume that the total weight of the desired blend is 100 pounds]
This question is from textbook New Mexico Edition College Algebra
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a coffee manufacturer wants to market a new blend of coffee that sells for $3.90 per pound by mixing two coffees that sell for $2.75 and $5.00 per pound, respectively.
What amounts of each coffee should be blended to obtain the desired mixture? [Hint: Assume "a" and "b"
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Quantity equation: a + b = 100 lbs
Value equation: 2.75a + 5b = 3.90*100
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Solve by any means to get:
a = 48.89 lbs (amt of 2.75 coffee in mixture)
b = 51.11 lbs (amt of $5 coffee in mixture)
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Cheers,
Stan H.
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