# SOLUTION: Tickets for a train ride were \$120 for a sleeping room, \$80 dollars for a berth, and \$50 for a coach seat. The total ticket sales were \$8600. If there were 20 more berth tickets th

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 Question 145297: Tickets for a train ride were \$120 for a sleeping room, \$80 dollars for a berth, and \$50 for a coach seat. The total ticket sales were \$8600. If there were 20 more berth tickets than sleeping room tickets and 3 times as many coach tickets as sleeping room tickets, how many of each type of ticket were sold?Answer by ankor@dixie-net.com(15622)   (Show Source): You can put this solution on YOUR website!Let x = no. of rooms Let y = no. of berths Let z = no. of seats : Write an equation for each statement: : "Tickets for a train ride were \$120 for a sleeping room, \$80 dollars for a berth, and \$50 for a coach seat. The total ticket sales were \$8600." 120x + 80y + 50z = 8600 : "there were 20 more berth tickets than sleeping room tickets" y = x + 20 : " 3 times as many coach tickets as sleeping room tickets," z = 3x : how many of each type of ticket were sold? : Substitute (x+20) for y and 3x for z in the 1st equation: 120x + 80(x+20) + 50(3x) = 8600 : 120x + 80x + 1600 + 150x = 8600; multiplied whats in the brackets : 120x + 80x + 150x = 8600 - 1600; subtracted 1600 from both sides : 350x = 7000 x = x = 20 sleeping room tickets : I'll let you find y and z using the 2nd and 3rd equations : Check your solutions in the \$total equation