SOLUTION: Hi me again. I mostly having trouble with word problems *Math worst subject*, anyway, with this I started than got confused:
*When the digits of a two-digit number are reversed,
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Question 129940This question is from textbook algebra
: Hi me again. I mostly having trouble with word problems *Math worst subject*, anyway, with this I started than got confused:
*When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number?*
I am always thankful, or gonna be thankful when you guys help me, I always wanted help with this algebra book. Thankfully I got it.
Please and Thank You=)
This question is from textbook algebra
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let t=ten's digit of unknown number, u=unit's digit of unknown number
So our number is in this form
Now if the digits are reversed then our number becomes
Since the new number is 9 more than the original number, this means
Also, because the sum of the digits of the original number is 11, we know that
And solving for t, we get
Start with the third equation
Plug in and
Plug in . Notice how we now have one equation with one unknown
Distribute
Combine like terms on the left side
Combine like terms on the right side
Subtract 11 from both sides
Add 9u to both sides
Combine like terms on the left side
Combine like terms on the right side
Divide both sides by 18 to isolate u
Divide
So we know that the unit's digit is 6
Plug in
Subtract
So the ten's digit is 5
So the original number is 56 and the reversed number is 65
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