SOLUTION: Hi me again. I mostly having trouble with word problems *Math worst subject*, anyway, with this I started than got confused: *When the digits of a two-digit number are reversed,

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Question 129940This question is from textbook algebra
: Hi me again. I mostly having trouble with word problems *Math worst subject*, anyway, with this I started than got confused:
*When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number?*
I am always thankful, or gonna be thankful when you guys help me, I always wanted help with this algebra book. Thankfully I got it.
Please and Thank You=)
This question is from textbook algebra

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let t=ten's digit of unknown number, u=unit's digit of unknown number


So our number is in this form




Now if the digits are reversed then our number becomes





Since the new number is 9 more than the original number, this means




Also, because the sum of the digits of the original number is 11, we know that





And solving for t, we get







Start with the third equation


Plug in and


Plug in . Notice how we now have one equation with one unknown



Distribute


Combine like terms on the left side


Combine like terms on the right side


Subtract 11 from both sides


Add 9u to both sides


Combine like terms on the left side


Combine like terms on the right side


Divide both sides by 18 to isolate u



Divide

So we know that the unit's digit is 6



Plug in


Subtract


So the ten's digit is 5




So the original number is 56 and the reversed number is 65




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