You can
put this solution on YOUR website!the problem gives the relationship between the interest rates and the amount of interest
__ I=Prt is appropriate because the values of the accounts (A) aren't used
__ since the time is the same for both, it can be ignored
let x="interest on $8000", so x+.01="interest on $9000"
(x)(8000)+165=(x+.01)(9000) __ 8000x+165=9000x+90 __ 75=1000x __ .075=x
converting to % __ x=7.5%