SOLUTION: The length of a rectangle is 1 in. more than twice its width. If the perimeter of the rectangle is 26 in., find the width of the rectangle. I have four choices (4 in, 5 in, 6 in,

Question 127441: The length of a rectangle is 1 in. more than twice its width. If the perimeter of the rectangle is 26 in., find the width of the rectangle. I have four choices (4 in, 5 in, 6 in, or 3 in.). I came up with 6 inches but this doesn't feel right. Is this correct? Thanks so much.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let the width be W and the length be L.
The perimeter of a rectangle is given by:
and this, you are told, is 26 inches.
You also know that the length L is 1 more than twice the width, W, so you can write:
Now substitute this into the formula for the perimeter to get:
Simplify and solve for W.

Subtract 2 from both sides.
Divide both sides by 6.

The width is 4 inches.
Check:

Substitute W = 4.

It checks!
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